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why my power calculation for this resistor is wrong?

i encountered a very simple question in a test and i easily calculated the answer
but somehow i am making a mistake because i can not find my answer between the available answers, what am i doing wrong ?
thanks.

Question : Calculate the wasted power on the 6 ohm resistor.
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my current answer using KVL :
(i*2) – 16 – (4*i) + 4 + (6 * i) – (3 * (4 * i)) = 0
(- 8 * i) = 12
i = -(12 / 8) A

now power for 6 ohm resistor
p = vi = i^2 * r
p = ((12 / 8) ^ 2) * 6 = 13.5 w


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